Algebraic Manipulation Examples in Math

Start with the recap, study the fully worked examples, then use the practice problems to check your understanding of Algebraic Manipulation.

This page combines explanation, solved examples, and follow-up practice so you can move from recognition to confident problem-solving in Math.

Concept Recap

Algebraic manipulation is the process of rewriting expressions or equations into equivalent forms to reveal structure or solve for unknowns.

It is like rearranging a sentence without changing its meaning.

Read the full concept explanation โ†’

How to Use These Examples

  • Read the first worked example with the solution open so the structure is clear.
  • Try the practice problems before revealing each solution.
  • Use the related concepts and background knowledge badges if you feel stuck.

What to Focus On

Core idea: Algebraic manipulation turns an expression or equation into an equivalent one to expose structure or isolate an unknown, without ever changing which values make it true.

Common stuck point: The procedure for algebraic manipulation is the easy part; the trap is changing only one side of an equation. Asking "Does every step keep exactly the same set of true values, just written differently?" first is what keeps a correct-looking calculation from being attached to the wrong concept.

Sense of Study hint: Ask: Does every step keep exactly the same set of true values, just written differently?

Worked Examples

Example 1

easy
Simplify 2(x+3)โˆ’x2(x + 3) - x.

Answer

x+6x + 6

First step

1
Step 1: Distribute: 2x+6โˆ’x2x + 6 - x.

Full solution

  1. 2
    Step 2: Combine like terms: x+6x + 6.
  2. 3
    Check: At x=1x = 1: 2(4)โˆ’1=72(4) - 1 = 7 and 1+6=71 + 6 = 7 โœ“
Algebraic manipulation is the process of rewriting expressions using distribution and combining like terms to reach a simpler or more useful equivalent form.

Example 2

medium
Solve for yy: 3yโˆ’2(y+4)=y+63y - 2(y + 4) = y + 6.

Example 3

medium
Solve 4xโˆ’7=2x+54x - 7 = 2x + 5.

Example 4

medium
Expand and simplify (xโˆ’3)(x+5)(x - 3)(x + 5).

Example 5

hard
Solve 2xโˆ’1x+3=3\dfrac{2x - 1}{x + 3} = 3 for xx.

Example 6

hard
Solve x+7=xโˆ’5\sqrt{x + 7} = x - 5 for real xx.

Practice Problems

Try these problems on your own first, then open the solution to compare your method.

Example 1

easy
Simplify 5xโˆ’3+2x+75x - 3 + 2x + 7.

Example 2

medium
Rearrange V=13ฯ€r2hV = \frac{1}{3}\pi r^2 h to solve for hh.

Example 3

easy
Simplify 3x+2x3x + 2x.

Example 4

easy
Expand 2(x+5)2(x + 5).

Example 5

easy
Solve x+7=12x + 7 = 12.

Example 6

easy
Solve 3x=213x = 21.

Example 7

easy
Factor 6x+96x + 9.

Example 8

easy
Simplify 4x2\dfrac{4x}{2}.

Example 9

easy
Combine 5aโˆ’3a+a5a - 3a + a.

Example 10

easy
Expand โˆ’(xโˆ’4)-(x - 4).

Example 11

medium
Solve 2x+3=112x + 3 = 11.

Example 12

medium
Solve 5xโˆ’2=3x+85x - 2 = 3x + 8.

Example 13

medium
Simplify x+3x\dfrac{x+3}{x} as far as possible.

Example 14

medium
Solve for yy: 3x+2y=123x + 2y = 12.

Example 15

medium
Expand and simplify (x+2)(x+3)(x+2)(x+3).

Example 16

medium
Solve x4+1=3\dfrac{x}{4} + 1 = 3.

Example 17

medium
Factor x2+7x+12x^2 + 7x + 12.

Example 18

medium
Solve 2(xโˆ’1)=x+42(x - 1) = x + 4.

Example 19

challenge
Solve for xx: 1x+12=34\dfrac{1}{x} + \dfrac{1}{2} = \dfrac{3}{4}.

Example 20

challenge
Rewrite x2+6x+5x^2 + 6x + 5 by completing the square.

Example 21

challenge
If x+1x=4x + \dfrac{1}{x} = 4, find x2+1x2x^2 + \dfrac{1}{x^2}.

Example 22

medium
Solve 2xโˆ’13=5\dfrac{2x - 1}{3} = 5.

Example 23

easy
Simplify 4a+2โˆ’a+54a + 2 - a + 5.

Example 24

easy
Expand 3(2xโˆ’4)3(2x - 4).

Example 25

easy
Factor 10xโˆ’1510x - 15.

Example 26

easy
Expand โˆ’3(x+2)-3(x + 2).

Example 27

easy
Combine 6y+4โˆ’2yโˆ’16y + 4 - 2y - 1.

Example 28

medium
Solve 3(xโˆ’2)=2x+53(x - 2) = 2x + 5.

Example 29

medium
Rearrange A=12bhA = \dfrac{1}{2}bh to solve for bb.

Example 30

medium
Simplify 6x+93\dfrac{6x + 9}{3}.

Example 31

medium
Solve x+42=7\dfrac{x + 4}{2} = 7.

Example 32

medium
Solve for rr: C=2ฯ€rC = 2\pi r.

Example 33

medium
Factor x2โˆ’5xโˆ’24x^2 - 5x - 24.

Example 34

medium
Simplify x2โˆ’9xโˆ’3\dfrac{x^2 - 9}{x - 3} for xโ‰ 3x \ne 3.

Example 35

hard
Solve 1xโˆ’1+1x+1=12\dfrac{1}{x - 1} + \dfrac{1}{x + 1} = \dfrac{1}{2} for the larger real xx.

Example 36

hard
Rearrange 1f=1u+1v\dfrac{1}{f} = \dfrac{1}{u} + \dfrac{1}{v} to solve for vv.

Example 37

hard
Solve โˆฃ2xโˆ’5โˆฃ=9|2x - 5| = 9.

Example 38

hard
Simplify x2โˆ’xโˆ’6x2โˆ’9\dfrac{x^2 - x - 6}{x^2 - 9} for xโ‰ ยฑ3x \ne \pm 3.

Example 39

hard
Solve the system 2x+3y=122x + 3y = 12 and xโˆ’y=1x - y = 1.

Example 40

challenge
If a+b=7a + b = 7 and a2+b2=29a^2 + b^2 = 29, find abab.

Example 41

challenge
Simplify (1xโˆ’1y)รท(xโˆ’yxy)\left( \dfrac{1}{x} - \dfrac{1}{y} \right) \div \left( \dfrac{x - y}{xy} \right) for nonzero xโ‰ yx \ne y.

Background Knowledge

These ideas may be useful before you work through the harder examples.

expressionsequivalence transformationbalance principle