Atomic Mass Chemistry Example 3

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Example 3

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Chlorine has two stable isotopes: 35Cl{}^{35}\text{Cl} (mass 34.97โ€‰amu34.97\,\text{amu}, 75.77%) and 37Cl{}^{37}\text{Cl} (mass 36.97โ€‰amu36.97\,\text{amu}, 24.23%). Calculate its atomic mass.

Solution

  1. 1
    mห‰=(34.97ร—0.7577)+(36.97ร—0.2423)\bar{m} = (34.97 \times 0.7577) + (36.97 \times 0.2423).
  2. 2
    mห‰=26.50+8.96=35.45โ€‰amu\bar{m} = 26.50 + 8.96 = 35.45\,\text{amu}.

Answer

35.45โ€‰amu35.45\,\text{amu}
Since 35Cl{}^{35}\text{Cl} is about three times more abundant than 37Cl{}^{37}\text{Cl}, the atomic mass is closer to 35 than to 37.

About Atomic Mass

The weighted average mass of all naturally occurring isotopes of an element, expressed in atomic mass units (amu), where each isotope's mass is weighted by.

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