Heat Transfer Physics Example 2

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Example 2

medium
A glass window (k=0.8 W/(m\cdotpK)k = 0.8 \text{ W/(m·K)}, area 2 m22 \text{ m}^2, thickness 0.005 m0.005 \text{ m}) has 20°C20°\text{C} inside and 5°C5°\text{C} outside. What is the rate of heat loss through the window?

Solution

  1. 1
    Use the conduction formula: Qt=kAΔTd\frac{Q}{t} = \frac{kA\Delta T}{d}.
  2. 2
    Qt=0.8×2×(205)0.005=0.8×2×150.005\frac{Q}{t} = \frac{0.8 \times 2 \times (20 - 5)}{0.005} = \frac{0.8 \times 2 \times 15}{0.005}
  3. 3
    Qt=240.005=4800 W\frac{Q}{t} = \frac{24}{0.005} = 4800 \text{ W}

Answer

Qt=4800 W\frac{Q}{t} = 4800 \text{ W}
Heat conduction through a material depends on its thermal conductivity, the area, the temperature difference, and the thickness. Thicker windows and double glazing reduce heat loss significantly.

About Heat Transfer

The spontaneous flow of thermal energy from a hotter object to a cooler one until they reach thermal equilibrium (the same temperature).

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