Conservation of Momentum Physics Example 3

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Example 3

medium
A 60 kg60 \text{ kg} astronaut floating in space throws a 5 kg5 \text{ kg} tool at 8 m/s8 \text{ m/s}. What is the astronaut's recoil velocity?

Solution

  1. 1
    Initial total momentum is zero (both at rest).
  2. 2
    By conservation of momentum: 0=mava+mtvt    va=mtvtma=5×8600 = m_a v_a + m_t v_t \implies v_a = -\frac{m_t v_t}{m_a} = -\frac{5 \times 8}{60}
  3. 3
    va=0.67 m/sv_a = -0.67 \text{ m/s}

Answer

vastronaut0.67 m/s (opposite direction)v_{\text{astronaut}} \approx 0.67 \text{ m/s (opposite direction)}
Conservation of momentum applies in isolated systems. The astronaut recoils in the opposite direction to the thrown tool, with a smaller speed due to greater mass.

About Conservation of Momentum

In a closed system with no net external force, the total momentum of all objects remains constant before and after any interaction — momentum is.

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