Conservation of Momentum Physics Example 2

Solution

1. 1
   In an elastic collision between equal masses where one is at rest, the first object stops and the second moves with the first object's initial velocity.
2. 2
   Conservation of momentum: $2(6) + 2(0) = 2v_1 + 2v_2 \implies v_1 + v_2 = 6$.
3. 3
   Conservation of kinetic energy: $\frac{1}{2}(2)(6^2) = \frac{1}{2}(2)(v_1^2) + \frac{1}{2}(2)(v_2^2) \implies v_1^2 + v_2^2 = 36$.
4. 4
   Solving: $v_1 = 0 \text{ m/s}$ and $v_2 = 6 \text{ m/s}$.