Similar Figures Math Example 2

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Example 2

hard
Rectangle ABCDโˆผABCD \sim Rectangle EFGHEFGH with AB=8AB = 8, BC=5BC = 5, EF=12EF = 12. Find FGFG and the ratio of areas.

Solution

  1. 1
    Scale factor: k=EFAB=128=32k = \dfrac{EF}{AB} = \dfrac{12}{8} = \dfrac{3}{2}.
  2. 2
    Since BCBC corresponds to FGFG: FG=5ร—32=7.5FG = 5 \times \dfrac{3}{2} = 7.5.
  3. 3
    Area of ABCD=8ร—5=40ABCD = 8 \times 5 = 40; Area of EFGH=12ร—7.5=90EFGH = 12 \times 7.5 = 90.
  4. 4
    Ratio of areas =9040=94=k2=(32)2= \dfrac{90}{40} = \dfrac{9}{4} = k^2 = \left(\dfrac{3}{2}\right)^2. โœ“

Answer

FG=7.5FG = 7.5; area ratio is 94\dfrac{9}{4}.
In similar figures, linear dimensions scale by kk while areas scale by k2k^2. Here k=32k = \frac{3}{2}, so the area ratio is 94\frac{9}{4}. This quadratic relationship between linear and area scaling is a fundamental property of similarity.

About Similar Figures

Similar figures have the same shape with corresponding angles equal and corresponding sides proportional.

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