Sequence Math Example 3

Follow the full solution, then compare it with the other examples linked below.

Example 3

easy
Write the first four terms of bn=(โˆ’1)nโ‹…1nb_n = (-1)^n \cdot \frac{1}{n}.

Solution

  1. 1
    b1=โˆ’1b_1 = -1, b2=12b_2 = \frac{1}{2}, b3=โˆ’13b_3 = -\frac{1}{3}, b4=14b_4 = \frac{1}{4}.

Answer

โˆ’1,โ€…โ€Š12,โ€…โ€Šโˆ’13,โ€…โ€Š14-1,\; \frac{1}{2},\; -\frac{1}{3},\; \frac{1}{4}
The factor (โˆ’1)n(-1)^n alternates the sign. Despite the oscillation, magnitudes 1/n1/n shrink to 0, so this alternating sequence converges to 0.

About Sequence

An ordered list of numbers generated by a rule, where each number has a specific position (first, second, third, ...).

Learn more about Sequence โ†’

More Sequence Examples