Related Rates Math Example 3

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Example 3

easy
A circle's radius grows at 3 cm/s. How fast is the area increasing when r=10r = 10 cm?

Solution

  1. 1
    A=ฯ€r2โ‡’dAdt=2ฯ€rdrdtA = \pi r^2 \Rightarrow \frac{dA}{dt} = 2\pi r \frac{dr}{dt}.
  2. 2
    At r=10r=10: dAdt=2ฯ€(10)(3)=60ฯ€\frac{dA}{dt} = 2\pi(10)(3) = 60\pi cmยฒ/s.

Answer

60ฯ€โ‰ˆ188.5ย cm2/s60\pi \approx 188.5 \text{ cm}^2/\text{s}
Differentiate the area formula with respect to time using the chain rule. Substitute the known radius and rate.

About Related Rates

Problems where two or more quantities change with time and are related by an equation. Differentiate the equation with respect to time tt and use known rates to find an unknown rate.

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