Mixed Numbers Math Example 2

Solution

1. 1
   Find the LCD of $3$ and $4$: $\text{LCD} = 12$.
2. 2
   Convert fractions: $4\frac{1}{3} = 4\frac{4}{12}$ and $1\frac{3}{4} = 1\frac{9}{12}$.
3. 3
   Since $\frac{4}{12} < \frac{9}{12}$, regroup: $4\frac{4}{12} = 3\frac{16}{12}$.
4. 4
   Subtract: whole parts $3 - 1 = 2$; fraction parts $\frac{16}{12} - \frac{9}{12} = \frac{7}{12}$.
5. 5
   Result: $2\frac{7}{12}$.