Evaluation Math Example 3

Follow the full solution, then compare it with the other examples linked below.

Example 3

easy
Evaluate โˆ’2x+10-2x + 10 when x=โˆ’3x = -3.

Solution

  1. 1
    Substitute: โˆ’2(โˆ’3)+10=6+10=16-2(-3) + 10 = 6 + 10 = 16.
  2. 2
    Be careful with the double negative: โˆ’2ร—โˆ’3=+6-2 \times -3 = +6.

Answer

1616
When substituting a negative value, use parentheses to avoid sign errors. Multiplying two negatives gives a positive.

About Evaluation

The process of calculating the numerical value of a mathematical expression by substituting specific numbers for each variable and then performing the indicated operations following the order of operations (PEMDAS/BODMAS).

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