Example 1 — Catch an extraneous root
EasyProblem
After solving , you get candidates and . Which are valid?
Solution
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Squaring was used, so candidates must be checked in the original equation.
Name the structure before touching arithmetic — that is what makes the right method obvious.
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Ask the recognition question: Do I have a candidate value that I plug into the original condition to confirm both sides are equal?
If the answer is yes, the concept applies; the cue, not a keyword, decides the method.
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Substitute each into and compare both sides.
The rule is chosen only after the structure matches, so the steps mean something.
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: true. : false.
Keep units, shape, or answer form tied to the story so the work does not become symbol pushing.
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Check the answer against the original question.
It should fit the mental model — plug it back in and see. If it does not, revisit the recognition step before changing the arithmetic.
Answer
Only is valid
Takeaway: Checking against the original equation exposes the extraneous root squaring introduced.