Checking Solutions Math Example 4

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Example 4

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Someone solved xxβˆ’2=2xβˆ’2\frac{x}{x-2} = \frac{2}{x-2} and got x=2x = 2. Is this valid?

Solution

  1. 1
    At x=2x = 2, the denominator xβˆ’2=0x - 2 = 0. Division by zero is undefined.
  2. 2
    x=2x = 2 is extraneousβ€”the equation has no solution.

Answer

Noβ€”x=2x = 2 makes the denominator zero. No solution.
Always check that solutions don't violate domain restrictions. Values making any denominator zero are excluded.

About Checking Solutions

Checking solutions means substituting candidate values back into the original condition to verify they satisfy it.

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