Arithmetic Sequence Math Example 3

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Example 3

easy
Find the 15th term of 4,9,14,19,โ€ฆ4, 9, 14, 19, \ldots

Solution

  1. 1
    a1=4a_1 = 4, d=5d = 5.
  2. 2
    a15=4+14(5)=74a_{15} = 4 + 14(5) = 74.

Answer

a15=74a_{15} = 74
Identify a1a_1 and dd, then apply an=a1+(nโˆ’1)da_n = a_1 + (n-1)d.

About Arithmetic Sequence

A sequence where each term is obtained from the previous by adding a fixed constant called the common difference dd.

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