Arithmetic Sequence Math Example 5

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Example 5

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Find the sum of the first 20 terms of the arithmetic sequence: 5, 8, 11, 14, ...

Solution

  1. 1
    Identify the first term a1=5a_1 = 5 and the common difference d=8โˆ’5=3d = 8 - 5 = 3.
  2. 2
    Find the 20th term: a20=a1+(20โˆ’1)d=5+19ร—3=5+57=62a_{20} = a_1 + (20 - 1)d = 5 + 19 \times 3 = 5 + 57 = 62.
  3. 3
    Apply the sum formula: S20=n2(a1+an)=202(5+62)=10ร—67=670S_{20} = \frac{n}{2}(a_1 + a_n) = \frac{20}{2}(5 + 62) = 10 \times 67 = 670.

Answer

S20=670S_{20} = 670
The sum of an arithmetic sequence uses the formula Sn=n2(a1+an)S_n = \frac{n}{2}(a_1 + a_n), which pairs the first and last terms, the second and second-to-last terms, and so on โ€” each pair has the same sum.

About Arithmetic Sequence

A sequence where each term is obtained from the previous by adding a fixed constant called the common difference dd.

Learn more about Arithmetic Sequence โ†’

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