Arithmetic Sequence Math Example 1

Follow the full solution, then compare it with the other examples linked below.

Example 1

easy
An arithmetic sequence has a1=7a_1 = 7 and d=โˆ’3d = -3. Find a20a_{20} and S20S_{20}.

Solution

  1. 1
    Use the arithmetic sequence formula to find the 20th term: an=a1+(nโˆ’1)da_n = a_1 + (n-1)d, where a1=7a_1 = 7, d=โˆ’3d = -3, n=20n = 20.
  2. 2
    Calculate: a20=7+(20โˆ’1)(โˆ’3)=7โˆ’57=โˆ’50a_{20} = 7 + (20-1)(-3) = 7 - 57 = -50
  3. 3
    Apply the partial sum formula: S20=202(a1+a20)=10(7+(โˆ’50))=10(โˆ’43)=โˆ’430S_{20} = \frac{20}{2}(a_1 + a_{20}) = 10(7 + (-50)) = 10(-43) = -430

Answer

a20=โˆ’50a_{20} = -50; S20=โˆ’430S_{20} = -430
With a negative common difference the sequence decreases. The sum formula averages the first and last terms and multiplies by the count.

About Arithmetic Sequence

A sequence where each term is obtained from the previous by adding a fixed constant called the common difference dd.

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