Solubility Chemistry Example 2

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Example 2

medium
Using a solubility curve, determine how many grams of KClO3\text{KClO}_3 can dissolve in 100100 g of water at 80°C80°\text{C} if the solubility is 40 g/100 g water40\,\text{g/100 g water}. If the solution is cooled to 30°C30°\text{C} where the solubility is 10 g/100 g water10\,\text{g/100 g water}, how much crystallizes out?

Solution

  1. 1
    At 80°C80°\text{C}: maximum dissolved KClO3=40\text{KClO}_3 = 40 g in 100100 g water (saturated solution).
  2. 2
    At 30°C30°\text{C}: maximum dissolved = 1010 g in 100100 g water.
  3. 3
    Mass crystallized = 40−10=3040 - 10 = 30 g of KClO3\text{KClO}_3.

Answer

30 g of KClO3 crystallizes upon cooling30\,\text{g of KClO}_3\text{ crystallizes upon cooling}
Solubility curves graphically show how solubility changes with temperature. The difference between solubilities at two temperatures tells us how much solute will precipitate when a saturated solution is cooled.

About Solubility

The maximum amount of a solute that can dissolve in a given quantity of solvent at a specific temperature and pressure, typically expressed as grams.

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