Simple Harmonic Motion Physics Example 3

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Example 3

medium
A 0.3 kg0.3 \text{ kg} mass on a spring oscillates with amplitude 0.1 m0.1 \text{ m} and period 0.8 s0.8 \text{ s}. What is the maximum speed of the mass?

Solution

  1. 1
    Angular frequency: ω=2πT=2π0.8=7.85 rad/s\omega = \frac{2\pi}{T} = \frac{2\pi}{0.8} = 7.85 \text{ rad/s}.
  2. 2
    Maximum speed in SHM occurs at the equilibrium position: vmax=ωA=7.85×0.1=0.785 m/sv_{\max} = \omega A = 7.85 \times 0.1 = 0.785 \text{ m/s}

Answer

vmax0.785 m/sv_{\max} \approx 0.785 \text{ m/s}
In simple harmonic motion, the maximum speed occurs as the object passes through equilibrium, where all energy is kinetic. At the extremes of oscillation, the speed is zero and all energy is potential.

About Simple Harmonic Motion

Oscillatory motion where the restoring force is proportional to displacement from equilibrium, producing sinusoidal position over time.

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