Simple Harmonic Motion Physics Example 2

Solution

1. 1
   Period of a simple pendulum: $T = 2\pi\sqrt{\frac{L}{g}}$.
2. 2
   On Earth: $T_E = 2\pi\sqrt{\frac{1}{9.8}} = 2\pi\sqrt{0.102} = 2\pi \times 0.319 \approx 2.01 \text{ s}$.
3. 3
   On the Moon: $T_M = 2\pi\sqrt{\frac{1}{1.6}} = 2\pi\sqrt{0.625} = 2\pi \times 0.791 \approx 4.97 \text{ s}$.