Mass Physics Example 2

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Example 2

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An astronaut has a mass of 75 kg75 \text{ kg}. What would their weight be on the Moon where gmoon=1.6 m/s2g_{\text{moon}} = 1.6 \text{ m/s}^2? Compare this to their weight on Earth (g=9.8 m/s2g = 9.8 \text{ m/s}^2).

Solution

  1. 1
    Calculate weight on the Moon: Wmoon=mgmoon=75×1.6=120 NW_{\text{moon}} = mg_{\text{moon}} = 75 \times 1.6 = 120 \text{ N}
  2. 2
    Calculate weight on Earth: Wearth=mg=75×9.8=735 NW_{\text{earth}} = mg = 75 \times 9.8 = 735 \text{ N}
  3. 3
    The astronaut's weight on the Moon is about 12073516%\frac{120}{735} \approx 16\% of their weight on Earth, but their mass remains 75 kg75 \text{ kg} in both locations.

Answer

Wmoon=120 N,Wearth=735 NW_{\text{moon}} = 120 \text{ N}, \quad W_{\text{earth}} = 735 \text{ N}
Mass is an intrinsic property of matter and does not change with location. Weight is the gravitational force on an object and varies with the local gravitational acceleration.

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The amount of matter in an object and a fundamental measure of how much it resists changes to its state of motion (inertia).

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