Gravitational Potential Energy Physics Example 2

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Example 2

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A 50 kg50 \text{ kg} person climbs a 15 m15 \text{ m} ladder. How much gravitational PE do they gain? Use g=9.8 m/s2g = 9.8 \text{ m/s}^2.

Solution

  1. 1
    Use the change in gravitational potential energy formula: ΔPE=mgΔh\Delta PE = mg\Delta h.
  2. 2
    Substitute the values: ΔPE=50×9.8×15\Delta PE = 50 \times 9.8 \times 15.
  3. 3
    ΔPE=7350 J\Delta PE = 7350 \text{ J}

Answer

ΔPE=7350 J\Delta PE = 7350 \text{ J}
Climbing increases gravitational PE. The work done against gravity is stored as PE and could be recovered (e.g., by sliding back down).

About Gravitational Potential Energy

Energy stored in an object due to its height above a reference point in a gravitational field: PE=mghPE = mgh.

Learn more about Gravitational Potential Energy →

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