Electric Field Physics Example 2

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Example 2

medium
A charge of 2ร—10โˆ’9ย C2 \times 10^{-9} \text{ C} is placed in an electric field of 5000ย N/C5000 \text{ N/C}. What force does it experience?

Solution

  1. 1
    Recall that the force on a charge placed in an electric field is: F=qEF = qE, where qq is charge and EE is field strength.
  2. 2
    Identify the given values: q=2ร—10โˆ’9โ€‰Cq = 2 \times 10^{-9}\,\text{C}, E=5000โ€‰N/CE = 5000\,\text{N/C}.
  3. 3
    Substitute and calculate: F=2ร—10โˆ’9ร—5000=1ร—10โˆ’5โ€‰NF = 2 \times 10^{-9} \times 5000 = 1 \times 10^{-5}\,\text{N}

Answer

F=1ร—10โˆ’5ย N=10ย ฮผNF = 1 \times 10^{-5} \text{ N} = 10 \text{ } \mu\text{N}
The electric field acts on charges placed within it. The force on a positive charge is in the direction of the field; on a negative charge, it is opposite.

About Electric Field

A region around a charged object where other charges experience a force. Measured in newtons per coulomb (N/C) or volts per meter (V/m).

Learn more about Electric Field โ†’

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