Acceleration Physics Example 4

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Example 4

medium
A cyclist accelerates uniformly from 4 m/s4 \text{ m/s} to 12 m/s12 \text{ m/s} over 8 seconds8 \text{ seconds}. (a) What is the acceleration? (b) How far does the cyclist travel during this time?

Solution

  1. 1
    (a) a=vut=1248=1 m/s2a = \frac{v - u}{t} = \frac{12 - 4}{8} = 1 \text{ m/s}^2.
  2. 2
    (b) s=ut+12at2=4(8)+12(1)(64)=32+32=64 ms = ut + \frac{1}{2}at^2 = 4(8) + \frac{1}{2}(1)(64) = 32 + 32 = 64 \text{ m}. Or: s=u+v2×t=4+122×8=64 ms = \frac{u + v}{2} \times t = \frac{4 + 12}{2} \times 8 = 64 \text{ m}.

Answer

(a)  1 m/s2;(b)  64 m(a)\; 1 \text{ m/s}^2; \quad (b)\; 64 \text{ m}
Uniform acceleration means a constant rate of velocity change. The SUVAT equations relate the five kinematic variables (s,u,v,a,ts, u, v, a, t). Using s=u+v2×ts = \frac{u+v}{2} \times t is often the quickest approach.

About Acceleration

The rate at which an object's velocity changes over time, measured in metres per second squared (m/s²).

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