Acceleration Physics Example 3

Follow the full solution, then compare it with the other examples linked below.

medium

An object starts from rest and accelerates at

3 \text{ m/s}^2

for

8 \text{ s}

. What is the final velocity and distance traveled?

1
Final velocity: $v = v_0 + at = 0 + 3 \times 8 = 24 \text{ m/s}$ .
2
Distance: $d = v_0 t + \frac{1}{2}at^2 = 0 + \frac{1}{2}(3)(64) = 96 \text{ m}$

Answer

v = 24 \text{ m/s}, \quad d = 96 \text{ m}

Starting from rest simplifies the kinematic equations. The distance grows quadratically with time under constant acceleration.

About Acceleration

The rate at which an object's velocity changes over time, measured in metres per second squared (m/s²).

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