Word Problems Math Example 2

Solution

1. 1
   Let $w$ be the width. Then the length is $l = 2w + 3$.
2. 2
   Perimeter formula: $2l + 2w = 56$, so $2(2w + 3) + 2w = 56$.
3. 3
   Expand: $4w + 6 + 2w = 56$, giving $6w + 6 = 56$.
4. 4
   Solve: $6w = 50$, so $w = \frac{50}{6} = \frac{25}{3} \approx 8.33$ m.
5. 5
   Length: $l = 2(\frac{25}{3}) + 3 = \frac{50}{3} + \frac{9}{3} = \frac{59}{3} \approx 19.67$ m.