Vector Addition, Subtraction, and Scalar Multiplication Math Example 2

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Example 2

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Find uโˆ’v\mathbf{u} - \mathbf{v} where u=โŸจ2,5,โˆ’1โŸฉ\mathbf{u} = \langle 2, 5, -1 \rangle and v=โŸจ4,โˆ’3,2โŸฉ\mathbf{v} = \langle 4, -3, 2 \rangle.

Solution

  1. 1
    Step 1: Subtract component-wise: (2โˆ’4,5โˆ’(โˆ’3),โˆ’1โˆ’2)(2-4, 5-(-3), -1-2).
  2. 2
    Step 2: =โŸจโˆ’2,8,โˆ’3โŸฉ= \langle -2, 8, -3 \rangle.
  3. 3
    Check: uโˆ’v\mathbf{u} - \mathbf{v} is the vector from v\mathbf{v}'s tip to u\mathbf{u}'s tip โœ“

Answer

โŸจโˆ’2,8,โˆ’3โŸฉ\langle -2, 8, -3 \rangle
Vector subtraction uโˆ’v\mathbf{u} - \mathbf{v} can be thought of as u+(โˆ’v)\mathbf{u} + (-\mathbf{v}). Geometrically, it points from v\mathbf{v} to u\mathbf{u}.

About Vector Addition, Subtraction, and Scalar Multiplication

Vectors are added and subtracted component by component. Scalar multiplication multiplies each component of a vector by a number. If u=โŸจu1,u2โŸฉ\mathbf{u} = \langle u_1, u_2 \rangle and v=โŸจv1,v2โŸฉ\mathbf{v} = \langle v_1, v_2 \rangle, then u+v=โŸจu1+v1,u2+v2โŸฉ\mathbf{u} + \mathbf{v} = \langle u_1 + v_1, u_2 + v_2 \rangle and ku=โŸจku1,ku2โŸฉk\mathbf{u} = \langle ku_1, ku_2 \rangle.

Learn more about Vector Addition, Subtraction, and Scalar Multiplication โ†’

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