Tangent Line Math Example 1

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Example 1

easy
Find the equation of the tangent line to f(x)=x2+3f(x) = x^2 + 3 at x=2x = 2.

Solution

  1. 1
    Find the point of tangency: f(2)=4+3=7f(2) = 4 + 3 = 7. Point: (2,7)(2, 7).
  2. 2
    Find the slope: fโ€ฒ(x)=2xf'(x) = 2x, so fโ€ฒ(2)=4f'(2) = 4.
  3. 3
    Write the tangent line using point-slope form: yโˆ’7=4(xโˆ’2)y - 7 = 4(x - 2).
  4. 4
    Simplify: y=4xโˆ’8+7=4xโˆ’1y = 4x - 8 + 7 = 4x - 1.

Answer

y=4xโˆ’1y = 4x - 1
Two pieces of information define a line: a point and a slope. The point is (a,f(a))(a, f(a)) and the slope is fโ€ฒ(a)f'(a). Plug both into the point-slope formula yโˆ’f(a)=fโ€ฒ(a)(xโˆ’a)y - f(a) = f'(a)(x - a).

About Tangent Line

A line that touches a curve at exactly one point and has the same slope as the curve there.

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