Simplification Math Example 4

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Example 4

medium
Simplify the set expression (AB)(AB)(A \cup B) \cap (A \cup B') and justify each step.

Solution

  1. 1
    Apply the distributive law: (AB)(AB)=A(BB)(A \cup B) \cap (A \cup B') = A \cup (B \cap B').
  2. 2
    Since BB=B \cap B' = \emptyset (a set and its complement are disjoint): A=AA \cup \emptyset = A.
  3. 3
    Therefore (AB)(AB)=A(A \cup B) \cap (A \cup B') = A.

Answer

(AB)(AB)=A(A \cup B) \cap (A \cup B') = A
Set algebra mirrors Boolean algebra. Distributing union over intersection, then using complementation (BB=B \cap B' = \emptyset) and identity (A=AA \cup \emptyset = A) simplifies the expression to AA.

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