Simplification Examples in Math

Start with the recap, study the fully worked examples, then use the practice problems to check your understanding of Simplification.

This page combines explanation, solved examples, and follow-up practice so you can move from recognition to confident problem-solving in Math.

Concept Recap

The process of replacing a complex expression or model with a simpler equivalent that preserves the essential features.

The art of knowing what to throw away. Good simplification keeps the behavior that matters while discarding noise.

Read the full concept explanation →

How to Use These Examples

  • Read the first worked example with the solution open so the structure is clear.
  • Try the practice problems before revealing each solution.
  • Use the related concepts and background knowledge badges if you feel stuck.

What to Focus On

Core idea: Simplification replaces a complicated expression or model with an easier equivalent that still captures what matters.

Common stuck point: The procedure for simplification is the easy part; the trap is cancelling a factor without noting where it was zero. Asking "Am I making this easier to read while keeping the result that actually matters unchanged?" first is what keeps a correct-looking calculation from being attached to the wrong concept.

Sense of Study hint: Ask: Am I making this easier to read while keeping the result that actually matters unchanged?

Worked Examples

Example 1

easy
Simplify the Boolean expression p(pq)p \land (p \lor q) using absorption laws.

Answer

p(pq)pp \land (p \lor q) \equiv p

First step

1
The absorption law states: p(pq)pp \land (p \lor q) \equiv p.

Full solution

  1. 2
    Verify with truth table row (T,T)(T,T): pq=Tp \lor q = T; pT=T=pp \land T = T = p. Correct.
  2. 3
    Row (T,F)(T,F): pq=Tp \lor q = T; pT=T=pp \land T = T = p. Correct.
  3. 4
    Row (F,T)(F,T): pq=Tp \lor q = T; pT=F=pp \land T = F = p. Correct.
  4. 5
    Row (F,F)(F,F): pq=Fp \lor q = F; pF=F=pp \land F = F = p. Correct.
Absorption is a simplification law in Boolean algebra. If pp is true, then pqp \lor q is automatically true, so the conjunction just gives pp. If pp is false, both sides are false.

Example 2

medium
Simplify the algebraic expression x29x2x6\dfrac{x^2 - 9}{x^2 - x - 6} and state any restrictions.

Example 3

medium
Simplify 2x2+6x4x\dfrac{2x^2 + 6x}{4x} and state any restriction.

Example 4

medium
Simplify A(AB)A \cap (A \cup B) and justify.

Example 5

hard
Simplify x38x24\dfrac{x^3 - 8}{x^2 - 4} and state restrictions.

Example 6

challenge
A model has f(x)=1+2x+0.001x2f(x) = 1 + 2x + 0.001x^2. For x1|x| \le 1, justify the first-order simplification f(x)1+2xf(x) \approx 1 + 2x and bound the discarded error.

Practice Problems

Try these problems on your own first, then open the solution to compare your method.

Example 1

easy
Simplify: ¬(¬p)\neg(\neg p).

Example 2

medium
Simplify the set expression (AB)(AB)(A \cup B) \cap (A \cup B') and justify each step.

Example 3

easy
Simplify 6x3\frac{6x}{3}.

Example 4

easy
Simplify x+x+xx + x + x.

Example 5

easy
Simplify x2x\frac{x^2}{x} and state the domain restriction.

Example 6

easy
Simplify 2(x+3)+42(x+3) + 4.

Example 7

easy
Simplify 50\sqrt{50}.

Example 8

easy
Simplify the expression 0x+70 \cdot x + 7.

Example 9

easy
True or false: simplifying always means making an expression shorter.

Example 10

easy
Simplify 48\frac{4}{8} to lowest terms.

Example 11

medium
In a physics problem dominated by friction, a student drops the friction term to 'simplify'. Why is this a bad simplification?

Example 12

medium
Simplify x21x1\frac{x^2-1}{x-1} and state the restriction.

Example 13

medium
For small angles, replacing sinθ\sin\theta with θ\theta is a simplification. When does it break down?

Example 14

medium
Simplify the compound fraction 1234\dfrac{\tfrac{1}{2}}{\tfrac{3}{4}}.

Example 15

medium
Why does simplifying sinxsinx\frac{\sin x}{\sin x} to 11 require a stated restriction, and what is it?

Example 16

medium
A long polynomial 3x2+0x0+2x23x^2 + 0x - 0 + 2x^2 is given. Simplify and explain what makes this 'cleaner'.

Example 17

medium
To estimate 101\sqrt{101}, a student uses the linear approximation around 100=10\sqrt{100}=10. What simplification is being made, and what is the estimate?

Example 18

medium
Simplify ab+cb\frac{a}{b} + \frac{c}{b} and explain the structural simplification.

Example 19

medium
Simplify x2+2xx\frac{x^2+2x}{x} and state the restriction.

Example 20

challenge
Simplify 1x1x+1\frac{1}{x} - \frac{1}{x+1} into a single fraction, then explain why the result is 'simpler' for analyzing behavior as xx \to \infty.

Example 21

challenge
Simplify k=1n(1k1k+1)\sum_{k=1}^{n}\left(\frac{1}{k}-\frac{1}{k+1}\right) using telescoping, and state the closed form.

Example 22

challenge
A model has terms of orders 11, ϵ\epsilon, and ϵ2\epsilon^2 with ϵ=0.001\epsilon = 0.001. Justify which terms to keep for a first-order simplification and what error you incur.

Example 23

easy
Simplify 5x+3x2x5x + 3x - 2x.

Example 24

easy
Simplify 3(x+4)2(x1)3(x+4) - 2(x-1).

Example 25

easy
Simplify the Boolean expression pfalsep \lor \text{false}.

Example 26

easy
Simplify x3x2x\dfrac{x^3 \cdot x^2}{x}, stating any restriction.

Example 27

medium
Simplify x24x2\dfrac{x^2 - 4}{x - 2} and state any domain restriction.

Example 28

medium
Simplify the Boolean expression p(pq)p \lor (p \land q).

Example 29

medium
Simplify 1x+1+1x1\dfrac{1}{x+1} + \dfrac{1}{x-1} into a single fraction.

Example 30

medium
Simplify x29x26x+9\dfrac{x^2 - 9}{x^2 - 6x + 9} stating the restriction.

Example 31

medium
Simplify ¬(pq)\neg(p \lor q) using De Morgan's law.

Example 32

medium
Simplify (x+1)(x2)(x2)(x+3)\dfrac{(x+1)(x-2)}{(x-2)(x+3)} and state restrictions.

Example 33

hard
Simplify 1x1yxy\dfrac{\frac{1}{x} - \frac{1}{y}}{x - y} for xyx \ne y, xy0xy \ne 0.

Example 34

hard
Simplify sin2θ+cos2θ+tan2θsec2θ\sin^2\theta + \cos^2\theta + \tan^2\theta - \sec^2\theta.

Example 35

hard
Simplify logb ⁣(b5x2x)\log_b\!\left(\dfrac{b^5 x^2}{x}\right) for x>0x>0.

Example 36

challenge
For small xx, the linear approximation 1+x1+x/2\sqrt{1+x}\approx 1 + x/2 is used. Use it to estimate 1.04\sqrt{1.04}, and bound the error.

Background Knowledge

These ideas may be useful before you work through the harder examples.

abstraction