Similarity Criteria Math Example 4

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Example 4

easy
A tree casts a 15 m shadow, and at the same time a 2 m stick casts a 3 m shadow. How tall is the tree? Which similarity criterion justifies this method?

Solution

  1. 1
    Step 1: The sun's rays are parallel, so the angle of elevation of the sun is the same for both the tree and the stick. Both also form right angles with the ground. By AA, the two triangles formed are similar.
  2. 2
    Step 2: Set up the proportion: tree heighttree shadow=stick heightstick shadow\frac{\text{tree height}}{\text{tree shadow}} = \frac{\text{stick height}}{\text{stick shadow}}, so h15=23\frac{h}{15} = \frac{2}{3}.
  3. 3
    Step 3: Solve: h=15×23=10h = 15 \times \frac{2}{3} = 10 m.

Answer

The tree is 10 m tall. AA similarity justifies the method.
Shadow problems use AA similarity: both triangles share the same sun angle (corresponding angles) and both have a right angle (the vertical object meets the ground at 90°). With two equal angles, AA guarantees similarity, so the sides are proportional and we can set up and solve the shadow proportion.

About Similarity Criteria

Three sets of conditions that guarantee two triangles are similar: AA (two pairs of equal angles), SAS~ (two pairs of proportional sides with equal included angle), and SSS~ (all three pairs of sides in the same ratio).

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