Sigma Notation Examples in Math

Start with the recap, study the fully worked examples, then use the practice problems to check your understanding of Sigma Notation.

This page combines explanation, solved examples, and follow-up practice so you can move from recognition to confident problem-solving in Math.

Concept Recap

Sigma notation uses the Greek letter ฮฃ to express the sum of many terms compactly. The expression โˆ‘i=1nai\sum_{i=1}^{n} a_i means 'add up aia_i for every integer ii from 1 to nn.' For example, โˆ‘i=14i2=1+4+9+16=30\sum_{i=1}^{4} i^2 = 1 + 4 + 9 + 16 = 30.

Sigma notation is shorthand for 'add these all up.' The letter below ฮฃ\Sigma is a counter, the number below is where to start, the number above is where to stop, and the expression to the right tells you what to add each time.

Read the full concept explanation โ†’

How to Use These Examples

  • Read the first worked example with the solution open so the structure is clear.
  • Try the practice problems before revealing each solution.
  • Use the related concepts and background knowledge badges if you feel stuck.

What to Focus On

Core idea: Sigma packs a long sum into a start, a stop, a counter, and a rule for each term.

Common stuck point: The procedure for sigma notation is the easy part; the trap is treating the term rule as a constant and multiplying by the number of terms. Asking "Is this an instruction to add up terms generated by substituting an index over a range?" first is what keeps a correct-looking calculation from being attached to the wrong concept.

Sense of Study hint: Ask: Is this an instruction to add up terms generated by substituting an index over a range?

Worked Examples

Example 1

easy
Expand and evaluate โˆ‘k=15(2kโˆ’1)\displaystyle\sum_{k=1}^{5} (2k - 1).

Answer

2525

First step

1
Write out each term: k=1:1k=1: 1, k=2:3k=2: 3, k=3:5k=3: 5, k=4:7k=4: 7, k=5:9k=5: 9.

Full solution

  1. 2
    Sum: 1+3+5+7+9=251+3+5+7+9 = 25.
  2. 3
    Alternatively, use linearity: 2โˆ‘k=15kโˆ’โˆ‘k=151=2โ‹…15โˆ’5=252\sum_{k=1}^5 k - \sum_{k=1}^5 1 = 2 \cdot 15 - 5 = 25.
Expanding by substituting each value of kk is the most direct approach. The linearity of ฮฃ\Sigma allows splitting the sum and using the formula โˆ‘k=1nk=n(n+1)2\sum_{k=1}^n k = \frac{n(n+1)}{2}.

Example 2

medium
Write 12+22+32+โ‹ฏ+n21^2 + 2^2 + 3^2 + \cdots + n^2 in sigma notation and evaluate the closed form for n=10n = 10.

Example 3

medium
Use the closed form to evaluate โˆ‘i=120i\sum_{i=1}^{20} i.

Example 4

medium
Use linearity to evaluate โˆ‘i=110(4i+3)\sum_{i=1}^{10} (4i + 3).

Example 5

hard
Evaluate โˆ‘i=1ni3\sum_{i=1}^{n} i^3 for n=5n=5 using the closed form.

Example 6

hard
Use a closed form to simplify โˆ‘i=1n(2iโˆ’1)\sum_{i=1}^{n}(2i-1).

Example 7

medium
Shift the index: rewrite โˆ‘i=38(iโˆ’2)2\sum_{i=3}^{8} (i-2)^2 so it starts at j=1j=1.

Example 8

medium
Show โˆ‘i=1ncโ‹…ai=cโˆ‘i=1nai\sum_{i=1}^{n} c\cdot a_i = c\sum_{i=1}^{n} a_i by expanding for n=3n=3.

Example 9

hard
Use the telescoping identity to evaluate โˆ‘i=1n(1iโˆ’1i+1)\sum_{i=1}^{n} \left(\frac{1}{i} - \frac{1}{i+1}\right).

Example 10

challenge
Evaluate โˆ‘i=1100(3iโˆ’2)\sum_{i=1}^{100} (3i - 2) using closed forms.

Practice Problems

Try these problems on your own first, then open the solution to compare your method.

Example 1

easy
Evaluate โˆ‘i=043i\displaystyle\sum_{i=0}^{4} 3^i.

Example 2

medium
Rewrite โˆ‘j=1n(3j2+2jโˆ’1)\displaystyle\sum_{j=1}^{n}(3j^2 + 2j - 1) using linearity of summation.

Example 3

easy
Evaluate โˆ‘i=14i\sum_{i=1}^{4} i.

Example 4

easy
Evaluate โˆ‘i=13i2\sum_{i=1}^{3} i^2.

Example 5

easy
How many terms are in โˆ‘i=05ai\sum_{i=0}^{5} a_i?

Example 6

easy
Evaluate โˆ‘i=143\sum_{i=1}^{4} 3.

Example 7

easy
Evaluate โˆ‘i=24(2i)\sum_{i=2}^{4} (2i).

Example 8

easy
Use โˆ‘i=1ni=n(n+1)2\sum_{i=1}^{n} i = \frac{n(n+1)}{2} to evaluate โˆ‘i=110i\sum_{i=1}^{10} i.

Example 9

easy
Rewrite 2+4+6+8+102 + 4 + 6 + 8 + 10 in sigma notation.

Example 10

easy
Evaluate โˆ‘k=132k\sum_{k=1}^{3} 2^k.

Example 11

medium
Evaluate โˆ‘i=15(2i+1)\sum_{i=1}^{5} (2i + 1).

Example 12

medium
Evaluate โˆ‘i=14(i2โˆ’i)\sum_{i=1}^{4} (i^2 - i).

Example 13

medium
Evaluate โˆ‘i=36i\sum_{i=3}^{6} i using the shift idea โˆ‘i=16iโˆ’โˆ‘i=12i\sum_{i=1}^{6} i - \sum_{i=1}^{2} i.

Example 14

medium
Evaluate โˆ‘i=16i2\sum_{i=1}^{6} i^2 using n(n+1)(2n+1)6\frac{n(n+1)(2n+1)}{6}.

Example 15

medium
True or false: โˆ‘i=1n(aibi)=(โˆ‘ai)(โˆ‘bi)\sum_{i=1}^{n} (a_i b_i) = \left(\sum a_i\right)\left(\sum b_i\right). Justify with ai=bi=ia_i = b_i = i, n=2n=2.

Example 16

medium
Evaluate โˆ‘i=145โ‹…2iโˆ’1\sum_{i=1}^{4} 5 \cdot 2^{i-1}.

Example 17

medium
Rewrite โˆ‘i=1n(3iโˆ’2)\sum_{i=1}^{n} (3i - 2) as a single closed-form expression in nn.

Example 18

medium
Evaluate the double sum โˆ‘i=12โˆ‘j=13(i+j)\sum_{i=1}^{2}\sum_{j=1}^{3} (i + j).

Example 19

medium
Re-index โˆ‘i=15(i+2)2\sum_{i=1}^{5} (i+2)^2 as a sum of squares with shifted bounds, then evaluate.

Example 20

challenge
Find a closed form for โˆ‘i=1n1i(i+1)\sum_{i=1}^{n} \frac{1}{i(i+1)} and evaluate at n=99n=99.

Example 21

challenge
Evaluate โˆ‘i=1niโ‹…2i\sum_{i=1}^{n} i \cdot 2^{i} for n=4n = 4 and identify the general technique.

Example 22

challenge
Prove โˆ‘i=1n(2iโˆ’1)=n2\sum_{i=1}^{n} (2i - 1) = n^2 and use it to evaluate โˆ‘i=150(2iโˆ’1)\sum_{i=1}^{50}(2i-1).

Example 23

easy
Evaluate โˆ‘i=15i\sum_{i=1}^{5} i.

Example 24

easy
Evaluate โˆ‘i=14i2\sum_{i=1}^{4} i^2.

Example 25

easy
Evaluate โˆ‘i=157\sum_{i=1}^{5} 7.

Example 26

medium
Evaluate โˆ‘k=15(k2โˆ’k)\sum_{k=1}^{5} (k^2 - k).

Example 27

medium
Write 3+6+9+12+15+183 + 6 + 9 + 12 + 15 + 18 in sigma notation.

Example 28

medium
Write 1+1/2+1/4+1/8+1/161 + 1/2 + 1/4 + 1/8 + 1/16 in sigma notation.

Example 29

medium
Evaluate โˆ‘i=162i\sum_{i=1}^{6} 2^i.

Example 30

medium
Evaluate โˆ‘i=18(โˆ’1)i\sum_{i=1}^{8} (-1)^i.

Example 31

hard
Use โˆ‘i=n(n+1)/2\sum i = n(n+1)/2 and โˆ‘i2=n(n+1)(2n+1)/6\sum i^2 = n(n+1)(2n+1)/6 to evaluate โˆ‘i=1ni(i+1)\sum_{i=1}^{n} i(i+1) for n=6n=6.

Example 32

easy
In โˆ‘i=1nai\sum_{i=1}^{n} a_i, ii is called the ___.

Example 33

medium
Evaluate โˆ‘i=14(i+1)(iโˆ’1)\sum_{i=1}^{4} (i+1)(i-1).

Example 34

medium
What is the closed-form value of โˆ‘i=1n1\sum_{i=1}^{n} 1?

Example 35

medium
Evaluate โˆ‘i=141i(i+1)\sum_{i=1}^{4} \frac{1}{i(i+1)}.

Example 36

easy
Evaluate โˆ‘i=25(i2โˆ’1)\sum_{i=2}^{5} (i^2 - 1).

Example 37

hard
Express โˆ‘i=1n(2i+1)\sum_{i=1}^{n} (2i+1) in closed form.

Example 38

medium
Evaluate โˆ‘i=03(i2+1)\sum_{i=0}^{3} (i^2 + 1).

Background Knowledge

These ideas may be useful before you work through the harder examples.

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