Sigma Notation Examples: 48 Problems with Answers

Start with the recap, study the fully worked examples, then use the practice problems to check your understanding of Sigma Notation.

This page combines explanation, solved examples, and follow-up practice so you can move from recognition to confident problem-solving in Math.

Concept Recap

Sigma notation uses the Greek letter Σ to express the sum of many terms compactly. The expression ∑i=1nai means 'add up ai for every integer i from 1 to n.' For example, ∑i=14i2=1+4+9+16=30.

Sigma notation is shorthand for 'add these all up.' The letter below Σ is a counter, the number below is where to start, the number above is where to stop, and the expression to the right tells you what to add each time.

Read the full concept explanation →

How to Use These Examples

  • Read the first worked example with the solution open so the structure is clear.
  • Try the practice problems before revealing each solution.
  • Use the related concepts and background knowledge badges if you feel stuck.

What to Focus On

Core idea: Sigma packs a long sum into a start, a stop, a counter, and a rule for each term.

Common stuck point: The procedure for sigma notation is the easy part; the trap is treating the term rule as a constant and multiplying by the number of terms. Asking "Is this an instruction to add up terms generated by substituting an index over a range?" first is what keeps a correct-looking calculation from being attached to the wrong concept.

Sense of Study hint: Ask: Is this an instruction to add up terms generated by substituting an index over a range?

Worked Examples

Example 1

easy
Expand and evaluate ∑k=15(2k−1).

Answer

25

First step

1
Write out each term: k=1:1, k=2:3, k=3:5, k=4:7, k=5:9.

Full solution

  1. 2
    Sum: 1+3+5+7+9=25.
  2. 3
    Alternatively, use linearity: 2∑k=15k−∑k=151=2⋅15−5=25.
Expanding by substituting each value of k is the most direct approach. The linearity of Σ allows splitting the sum and using the formula ∑k=1nk=n(n+1)2.

Example 2

medium
Write 12+22+32+⋯+n2 in sigma notation and evaluate the closed form for n=10.

Example 3

medium
Use the closed form to evaluate ∑i=120i.

Example 4

medium
Use linearity to evaluate ∑i=110(4i+3).

Example 5

hard
Evaluate ∑i=1ni3 for n=5 using the closed form.

Example 6

hard
Use a closed form to simplify ∑i=1n(2i−1).

Example 7

medium
Shift the index: rewrite ∑i=38(i−2)2 so it starts at j=1.

Example 8

medium
Show ∑i=1nc⋅ai=c∑i=1nai by expanding for n=3.

Example 9

hard
Use the telescoping identity to evaluate ∑i=1n(1i−1i+1).

Example 10

challenge
Evaluate ∑i=1100(3i−2) using closed forms.

Practice Problems

Try these problems on your own first, then open the solution to compare your method.

Example 1

easy
Evaluate ∑i=043i.

Example 2

medium
Rewrite ∑j=1n(3j2+2j−1) using linearity of summation.

Example 3

easy
Evaluate ∑i=14i.

Example 4

easy
Evaluate ∑i=13i2.

Example 5

easy
How many terms are in ∑i=05ai?

Example 6

easy
Evaluate ∑i=143.

Example 7

easy
Evaluate ∑i=24(2i).

Example 8

easy
Use ∑i=1ni=n(n+1)2 to evaluate ∑i=110i.

Example 9

easy
Rewrite 2+4+6+8+10 in sigma notation.

Example 10

easy
Evaluate ∑k=132k.

Example 11

medium
Evaluate ∑i=15(2i+1).

Example 12

medium
Evaluate ∑i=14(i2−i).

Example 13

medium
Evaluate ∑i=36i using the shift idea ∑i=16i−∑i=12i.

Example 14

medium
Evaluate ∑i=16i2 using n(n+1)(2n+1)6.

Example 15

medium
True or false: ∑i=1n(aibi)=(∑ai)(∑bi). Justify with ai=bi=i, n=2.

Example 16

medium
Evaluate ∑i=145⋅2i−1.

Example 17

medium
Rewrite ∑i=1n(3i−2) as a single closed-form expression in n.

Example 18

medium
Evaluate the double sum ∑i=12∑j=13(i+j).

Example 19

medium
Re-index ∑i=15(i+2)2 as a sum of squares with shifted bounds, then evaluate.

Example 20

challenge
Find a closed form for ∑i=1n1i(i+1) and evaluate at n=99.

Example 21

challenge
Evaluate ∑i=1ni⋅2i for n=4 and identify the general technique.

Example 22

challenge
Prove ∑i=1n(2i−1)=n2 and use it to evaluate ∑i=150(2i−1).

Example 23

easy
Evaluate ∑i=15i.

Example 24

easy
Evaluate ∑i=14i2.

Example 25

easy
Evaluate ∑i=157.

Example 26

medium
Evaluate ∑k=15(k2−k).

Example 27

medium
Write 3+6+9+12+15+18 in sigma notation.

Example 28

medium
Write 1+1/2+1/4+1/8+1/16 in sigma notation.

Example 29

medium
Evaluate ∑i=162i.

Example 30

medium
Evaluate ∑i=18(−1)i.

Example 31

hard
Use ∑i=n(n+1)/2 and ∑i2=n(n+1)(2n+1)/6 to evaluate ∑i=1ni(i+1) for n=6.

Example 32

easy
In ∑i=1nai, i is called the ___.

Example 33

medium
Evaluate ∑i=14(i+1)(i−1).

Example 34

medium
What is the closed-form value of ∑i=1n1?

Example 35

medium
Evaluate ∑i=141i(i+1).

Example 36

easy
Evaluate ∑i=25(i2−1).

Example 37

hard
Express ∑i=1n(2i+1) in closed form.

Example 38

medium
Evaluate ∑i=03(i2+1).

Background Knowledge

These ideas may be useful before you work through the harder examples.

sequenceseries