Sector Area Math Example 4

Follow the full solution, then compare it with the other examples linked below.

Example 4

hard
A sprinkler rotates through an angle of 120ยฐ120ยฐ and waters grass up to a radius of 1515 ft. What area of grass does it water? If the water only reaches between 1010 ft and 1515 ft from the sprinkler, what annular sector area gets watered?

Solution

  1. 1
    Step 1: Full sector area (radius 15 ft, 120ยฐ): Afull=120360ร—ฯ€(15)2=13ร—225ฯ€=75ฯ€โ‰ˆ235.6A_{\text{full}} = \frac{120}{360} \times \pi(15)^2 = \frac{1}{3} \times 225\pi = 75\pi \approx 235.6 ftยฒ.
  2. 2
    Step 2: Inner sector area (radius 10 ft, 120ยฐ): Ainner=120360ร—ฯ€(10)2=13ร—100ฯ€=100ฯ€3โ‰ˆ104.7A_{\text{inner}} = \frac{120}{360} \times \pi(10)^2 = \frac{1}{3} \times 100\pi = \frac{100\pi}{3} \approx 104.7 ftยฒ.
  3. 3
    Step 3: Annular sector area =Afullโˆ’Ainner=75ฯ€โˆ’100ฯ€3=225ฯ€โˆ’100ฯ€3=125ฯ€3โ‰ˆ130.9= A_{\text{full}} - A_{\text{inner}} = 75\pi - \frac{100\pi}{3} = \frac{225\pi - 100\pi}{3} = \frac{125\pi}{3} \approx 130.9 ftยฒ.

Answer

Full sector: 75ฯ€โ‰ˆ235.675\pi \approx 235.6 ftยฒ; Annular sector: 125ฯ€3โ‰ˆ130.9\frac{125\pi}{3} \approx 130.9 ftยฒ
The annular sector (ring-shaped sector) is found by subtracting the smaller inner sector from the larger outer sector. This technique of combining or subtracting standard shapes is key for composite area problems.

About Sector Area

The area of a 'pie slice' region of a circle, bounded by two radii and the arc between them.

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