Sector Area Math Example 1

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Example 1

easy
Find the area of a sector of a circle with radius 88 cm and central angle 90°90°.

Solution

  1. 1
    Step 1: Write the sector area formula in degrees: A=θ360°×πr2A = \frac{\theta}{360°} \times \pi r^2.
  2. 2
    Step 2: Substitute θ=90°\theta = 90° and r=8r = 8 cm: A=90360×π(8)2A = \frac{90}{360} \times \pi (8)^2.
  3. 3
    Step 3: Simplify the fraction: 90360=14\frac{90}{360} = \frac{1}{4}, and r2=64r^2 = 64.
  4. 4
    Step 4: Compute: A=14×64π=16π50.27A = \frac{1}{4} \times 64\pi = 16\pi \approx 50.27 cm².

Answer

A=16π50.27A = 16\pi \approx 50.27 cm²
A 90° sector is one-quarter of the full circle. One-quarter of the circle's area π(8)2=64π\pi(8)^2 = 64\pi cm² gives 16π16\pi cm². This matches 14πr2\frac{1}{4}\pi r^2 for a quarter-circle.

About Sector Area

The area of a 'pie slice' region of a circle, bounded by two radii and the arc between them.

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