Riemann Sums Math Example 4

Follow the full solution, then compare it with the other examples linked below.

Example 4

hard
Write the right Riemann sum for โˆซ01x3โ€‰dx\int_0^1 x^3\,dx with nn subintervals as a sigma expression and evaluate the limit.

Solution

  1. 1
    ฮ”x=1n\Delta x = \frac{1}{n}, right endpoints xi=inx_i = \frac{i}{n}.
  2. 2
    Rn=โˆ‘i=1n(in)31n=1n4โˆ‘i=1ni3R_n = \sum_{i=1}^{n}\left(\frac{i}{n}\right)^3 \frac{1}{n} = \frac{1}{n^4}\sum_{i=1}^{n} i^3.
  3. 3
    Using โˆ‘i=1ni3=(n(n+1)2)2\sum_{i=1}^n i^3 = \left(\frac{n(n+1)}{2}\right)^2: Rn=(n+1)24n2R_n = \frac{(n+1)^2}{4n^2}.
  4. 4
    limโกnโ†’โˆžRn=14\lim_{n\to\infty} R_n = \frac{1}{4}.

Answer

โˆซ01x3โ€‰dx=14\int_0^1 x^3\,dx = \frac{1}{4}
This confirms the definition of the definite integral as a limit of Riemann sums, recovering the FTC result [x44]01=14\left[\frac{x^4}{4}\right]_0^1 = \frac{1}{4}.

About Riemann Sums

A method of approximating the definite integral โˆซabf(x)โ€‰dx\int_a^b f(x)\,dx by dividing the interval [a,b][a, b] into subintervals and summing the areas of rectangles (or trapezoids) whose heights are determined by the function.

Learn more about Riemann Sums โ†’

More Riemann Sums Examples