Riemann Sums Math Example 2

Follow the full solution, then compare it with the other examples linked below.

Example 2

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Approximate โˆซ131xโ€‰dx\int_1^3 \frac{1}{x}\,dx using a right Riemann sum with n=4n = 4 subintervals and classify the estimate.

Solution

  1. 1
    ฮ”x=0.5\Delta x = 0.5. Right endpoints: x=1.5,2,2.5,3x = 1.5, 2, 2.5, 3.
  2. 2
    f(1.5)โ‰ˆ0.667,โ€…โ€Šf(2)=0.5,โ€…โ€Šf(2.5)=0.4,โ€…โ€Šf(3)โ‰ˆ0.333f(1.5) \approx 0.667,\; f(2)=0.5,\; f(2.5)=0.4,\; f(3) \approx 0.333.
  3. 3
    R4=0.5(0.667+0.5+0.4+0.333)=0.5ร—1.9=0.95R_4 = 0.5(0.667+0.5+0.4+0.333) = 0.5 \times 1.9 = 0.95.
  4. 4
    ff is decreasing, so right endpoints give minima: underestimate. Exact: lnโก3โ‰ˆ1.099\ln 3 \approx 1.099.

Answer

R4=0.95R_4 = 0.95 (underestimate; exact =lnโก3โ‰ˆ1.099= \ln 3 \approx 1.099)
For a decreasing function, right endpoints use the smallest value in each subinterval, giving an underestimate.

About Riemann Sums

A method of approximating the definite integral โˆซabf(x)โ€‰dx\int_a^b f(x)\,dx by dividing the interval [a,b][a, b] into subintervals and summing the areas of rectangles (or trapezoids) whose heights are determined by the function.

Learn more about Riemann Sums โ†’

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