Riemann Sums Math Example 1

Follow the full solution, then compare it with the other examples linked below.

Example 1

easy
Approximate โˆซ02x2โ€‰dx\int_0^2 x^2\,dx using a left Riemann sum with n=4n = 4 equal subintervals.

Solution

  1. 1
    ฮ”x=0.5\Delta x = 0.5. Left endpoints: x=0,0.5,1,1.5x = 0, 0.5, 1, 1.5.
  2. 2
    f(0)=0,โ€…โ€Šf(0.5)=0.25,โ€…โ€Šf(1)=1,โ€…โ€Šf(1.5)=2.25f(0)=0,\; f(0.5)=0.25,\; f(1)=1,\; f(1.5)=2.25.
  3. 3
    L4=0.5(0+0.25+1+2.25)=0.5ร—3.5=1.75L_4 = 0.5(0+0.25+1+2.25) = 0.5 \times 3.5 = 1.75.
  4. 4
    Exact value: 83โ‰ˆ2.667\frac{8}{3} \approx 2.667. The left sum underestimates because ff is increasing.

Answer

L4=1.75L_4 = 1.75 (underestimate; exact =83= \frac{8}{3})
For an increasing function, left endpoints give the minimum in each subinterval, so the left Riemann sum underestimates. More subintervals improve accuracy.

About Riemann Sums

A method of approximating the definite integral โˆซabf(x)โ€‰dx\int_a^b f(x)\,dx by dividing the interval [a,b][a, b] into subintervals and summing the areas of rectangles (or trapezoids) whose heights are determined by the function.

Learn more about Riemann Sums โ†’

More Riemann Sums Examples