Practice Indirect Measurement in Math

Use these practice problems to test your method after reviewing the concept explanation and worked examples.

Quick Recap

Indirect measurement finds unknown lengths by using proportional relationships instead of direct measuring tools.

Use a smaller, measurable shadow to infer a taller object’s height.

Showing a random 20 of 50 problems.

Example 1

medium
A 6-ft tall student is sighting a tree top. Holding a ruler 24 inches from the eye, the tree top aligns with the 8-inch mark and the tree's base with the 0 mark. The student is 40 ft from the tree. Find the tree's total height.

Example 2

hard
To measure a tree across a river, a surveyor uses two stakes 60 m apart on the near shore. From the first stake the tree subtends an angle of 30° with the shoreline; from the second stake (closer along the shore), it subtends 90°. Find the perpendicular distance from the second stake to the tree.

Example 3

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A tree casts a shadow of 1515 m at the same time a 22 m pole casts a shadow of 33 m. How tall is the tree?

Example 4

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A scout sights a cliff using a clinometer reading 38° from 100 m away. Find the cliff height. (Use tan38°0.781\tan 38°\approx 0.781.)

Example 5

challenge
A 1 m stick at the edge of a flat field blocks the view of a distant 50 m tower exactly when held 0.4 m from the eye. How far away is the tower?

Example 6

medium
From 80 m away the angle of elevation to a tower top is 35°. Find the tower height. (Use tan35°0.700\tan 35°\approx 0.700.)

Example 7

easy
What two measurable quantities does the shadow method require?

Example 8

easy
A 5 ft stick casts a 3 ft shadow. A flagpole casts a 24 ft shadow. Find the flagpole's height.

Example 9

medium
A 2 m vertical stick casts a 3 m shadow. A nearby pole's shadow is 18 m. Find the pole's height.

Example 10

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To measure a pond's width, two stakes are set on one shore with AB=50AB=50 m. From BB, a tree across the water makes angle TBA=70°\angle TBA=70° with ABAB; the tree sits directly across from AA. Find the pond width. (Use tan70°2.747\tan 70°\approx 2.747.)

Example 11

easy
A photo (scale: 1 cm = 2 m) shows a building 7 cm tall. What is the real height?

Example 12

challenge
From a point, the angle of elevation to a tower top is 30°; moving 40 m closer it becomes 45°. Find the tower height (exact form).

Example 13

challenge
Astronomers measure stellar parallax: a star shifts by 0.5 arcseconds when Earth moves through a baseline of 2 AU (= 3×10113\times 10^{11} m). Estimate the distance to the star in meters. (Use 11 arcsecond =4.85×106=4.85\times 10^{-6} rad.)

Example 14

easy
Using a mirror placed 3 m from a tree: an observer with eyes 1.5 m above ground stands 1 m from the mirror and sees the tree top. Find the tree height.

Example 15

easy
A 1.5 m tall student casts a 1 m shadow. A nearby building casts a 12 m shadow. Find the building's height.

Example 16

medium
A 1.5 m tall student measures a 30° angle of elevation to a roof from 20 m away. Find the roof's height above the ground (use tan30°0.577\tan 30° \approx 0.577).

Example 17

easy
On a map with scale 1:50,000, two cities are 8 cm apart. What is the real distance?

Example 18

easy
Why does the shadow method for measuring heights work?

Example 19

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A 1.6 m tall student measures an elevation angle of 25° to a treetop from 30 m away. Find the tree height. (Use tan25°0.466\tan 25°\approx 0.466.)

Example 20

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A photo shows a person (real height 1.8 m) as 3 cm tall and a building as 25 cm tall. Estimate the building's real height.