Euler's Number Math Example 2

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Example 2

hard
Show that the derivative of f(x)=exf(x) = e^x is itself, i.e., fโ€ฒ(x)=exf'(x) = e^x, using the limit definition of the derivative.

Solution

  1. 1
    Apply the limit definition: fโ€ฒ(x)=limโกhโ†’0ex+hโˆ’exh=limโกhโ†’0ex(ehโˆ’1)h=exโ‹…limโกhโ†’0ehโˆ’1hf'(x) = \lim_{h \to 0}\frac{e^{x+h} - e^x}{h} = \lim_{h \to 0}\frac{e^x(e^h - 1)}{h} = e^x \cdot \lim_{h \to 0}\frac{e^h - 1}{h}.
  2. 2
    Evaluate the remaining limit using the Taylor expansion eh=1+h+h22!+โ‹ฏe^h = 1 + h + \frac{h^2}{2!} + \cdots, so ehโˆ’1h=1+h2!+โ‹ฏโ†’1\frac{e^h-1}{h} = 1 + \frac{h}{2!} + \cdots \to 1 as hโ†’0h \to 0.
  3. 3
    Therefore fโ€ฒ(x)=exโ‹…1=exf'(x) = e^x \cdot 1 = e^x. This self-referential property makes exe^x the unique exponential function equal to its own derivative.

Answer

ddxex=ex\frac{d}{dx}e^x = e^x
The fact that exe^x equals its own derivative is the defining characteristic of Euler's number. No other base axa^x satisfies ddxax=ax\frac{d}{dx}a^x = a^x without an extra multiplicative constant.

About Euler's Number

Euler's number eโ‰ˆ2.71828e \approx 2.71828 is the unique base for which the exponential function exe^x is its own derivative โ€” the natural base for growth and decay.

Learn more about Euler's Number โ†’

More Euler's Number Examples