Euler's Number Examples in Math

Start with the recap, study the fully worked examples, then use the practice problems to check your understanding of Euler's Number.

This page combines explanation, solved examples, and follow-up practice so you can move from recognition to confident problem-solving in Math.

Concept Recap

Euler's number eβ‰ˆ2.71828e \approx 2.71828 is the unique base for which the exponential function exe^x is its own derivative β€” the natural base for growth and decay.

The 'natural' base for growthβ€”what you get from continuous compounding.

Read the full concept explanation β†’

How to Use These Examples

  • Read the first worked example with the solution open so the structure is clear.
  • Try the practice problems before revealing each solution.
  • Use the related concepts and background knowledge badges if you feel stuck.

What to Focus On

Core idea: Euler's number eβ‰ˆ2.718e\approx 2.718 is the base whose exponential grows at a rate equal to its own value at every instant.

Common stuck point: The procedure for euler's number is the easy part; the trap is treating ee as a variable to solve for. Asking "Is the growth happening continuously, with the natural base where the rate equals the amount?" first is what keeps a correct-looking calculation from being attached to the wrong concept.

Sense of Study hint: Ask: Is the growth happening continuously, with the natural base where the rate equals the amount?

Worked Examples

Example 1

easy
Evaluate lim⁑nβ†’βˆž(1+1n)n\lim_{n \to \infty}\left(1 + \frac{1}{n}\right)^n and state what this limit defines.

Answer

eβ‰ˆ2.71828e \approx 2.71828

First step

1
Substitute increasing values of nn: for n=10n=10, (1+110)10β‰ˆ2.5937\left(1+\frac{1}{10}\right)^{10} \approx 2.5937; for n=100n=100, β‰ˆ2.7048\approx 2.7048; for n=1000n=1000, β‰ˆ2.7169\approx 2.7169.

Full solution

  1. 2
    Observe that as nβ†’βˆžn \to \infty the expression approaches a fixed value that does not grow without bound.
  2. 3
    By definition, lim⁑nβ†’βˆž(1+1n)n=eβ‰ˆ2.71828…\lim_{n \to \infty}\left(1+\frac{1}{n}\right)^n = e \approx 2.71828\ldots, Euler's number.
Euler's number ee is defined as this limit. It is irrational and transcendental, appearing naturally in continuous growth, calculus, and complex analysis.

Example 2

hard
Show that the derivative of f(x)=exf(x) = e^x is itself, i.e., fβ€²(x)=exf'(x) = e^x, using the limit definition of the derivative.

Example 3

medium
Simplify ln⁑(e7)\ln(e^7).

Example 4

medium
Carbon-14 decay: A(t)=A0eβˆ’0.000121tA(t) = A_0 e^{-0.000121 t} years. After 57305730 years, what fraction remains? Use eβˆ’0.693β‰ˆ0.5e^{-0.693}\approx 0.5.

Example 5

medium
Why does continuous compounding cap the limit of (1+r/n)nt(1+r/n)^{nt} at erte^{rt} as nβ†’βˆžn\to\infty?

Example 6

hard
Compare eΟ€e^\pi and Ο€e\pi^e. Use eΟ€β‰ˆ23.14e^\pi \approx 23.14 and Ο€eβ‰ˆ22.46\pi^e \approx 22.46.

Example 7

challenge
Using the series ex=βˆ‘k=0∞xkk!e^x = \sum_{k=0}^{\infty} \tfrac{x^k}{k!}, approximate ee using the first 5 terms (k=0k=0 to 44).

Practice Problems

Try these problems on your own first, then open the solution to compare your method.

Example 1

easy
Using a calculator, compute e2e^2 to four decimal places. Then determine whether e2>7e^2 > 7.

Example 2

medium
A bank offers continuous compounding at an annual rate of 5%5\%. Using A=PertA = Pe^{rt}, find how much $1000\$1000 grows to after 1010 years.

Example 3

easy
Is ee a variable or a constant?

Example 4

easy
Approximate e2e^2 using eβ‰ˆ2.718e\approx 2.718. (one decimal)

Example 5

easy
Which is larger: ee or Ο€\pi?

Example 6

easy
What is e0e^0?

Example 7

easy
The natural base ee arises from what kind of process?

Example 8

easy
Approximate e1e^1 to two decimals.

Example 9

easy
As nβ†’βˆžn\to\infty, what does (1+1n)n\left(1+\frac{1}{n}\right)^n approach?

Example 10

easy
Distinguish exe^x from xexe at x=2x=2 using eβ‰ˆ2.718e\approx 2.718.

Example 11

medium
A population grows as P(t)=100e0.5tP(t)=100e^{0.5t}. Find P(2)P(2) using eβ‰ˆ2.718e\approx 2.718.

Example 12

medium
Simplify e3β‹…e2e^3 \cdot e^2 to a single power of ee.

Example 13

medium
Simplify e7e4\dfrac{e^7}{e^4}.

Example 14

medium
Radioactive decay: A(t)=80eβˆ’0.1tA(t)=80e^{-0.1t}. Find A(0)A(0) and state the long-run limit.

Example 15

medium
Solve ex=1e^x = 1 for xx.

Example 16

medium
Order from smallest to largest: eβˆ’1e^{-1}, e0e^0, e1e^1. Use eβ‰ˆ2.718e\approx 2.718.

Example 17

medium
Continuous growth at rate r=0.03r=0.03 for t=10t=10 multiplies an amount by what factor? Use e0.3β‰ˆ1.3499e^{0.3}\approx 1.3499.

Example 18

medium
Why does exe^x have the special property among exponentials that its slope at any point equals its value?

Example 19

medium
Simplify (e2)3(e^2)^3 to a single power of ee.

Example 20

challenge
Solve 100e0.04t=200100e^{0.04t}=200 for tt. Use ln⁑2β‰ˆ0.693\ln 2\approx 0.693.

Example 21

challenge
Using (1+1/n)n(1+1/n)^n, estimate ee at n=2n=2 and explain why it underestimates ee.

Example 22

challenge
If ln⁑(A)=ln⁑(B)+3\ln(A)=\ln(B)+3, express AA in terms of BB.

Example 23

easy
Approximate eβˆ’1e^{-1} to three decimal places using eβ‰ˆ2.71828e \approx 2.71828.

Example 24

easy
Approximate (1+1/4)4(1+1/4)^4 as an estimate of ee. Round to three decimals.

Example 25

easy
Solve ex=e5e^x = e^5 for xx.

Example 26

easy
Which is larger, e2e^2 or 77? Use eβ‰ˆ2.718e \approx 2.718.

Example 27

medium
Continuous compounding: $500 at 4%4\% annual rate for 66 years. Find the amount. Use e0.24β‰ˆ1.27125e^{0.24}\approx 1.27125.

Example 28

medium
A bacterial culture follows N(t)=200e0.3tN(t) = 200 e^{0.3t} (hours). What is N(0)N(0) and the doubling time? Use ln⁑2β‰ˆ0.693\ln 2 \approx 0.693.

Example 29

medium
Simplify eln⁑5e^{\ln 5}.

Example 30

medium
Solve e2x=9e^{2x} = 9. Express xx using ln⁑\ln.

Example 31

medium
Find the slope of f(x)=exf(x)=e^x at x=0x=0.

Example 32

medium
Evaluate ∫01ex dx\int_0^1 e^x \, dx. Use eβ‰ˆ2.718e \approx 2.718.

Example 33

medium
Simplify e2xβ‹…e3ex\dfrac{e^{2x}\cdot e^{3}}{e^{x}} as a single power of ee.

Example 34

medium
A car loses value continuously: V(t)=20000eβˆ’0.15tV(t)=20000 e^{-0.15 t} dollars. Find V(5)V(5). Use eβˆ’0.75β‰ˆ0.4724e^{-0.75}\approx 0.4724.

Example 35

hard
Solve 3e2x=243 e^{2x} = 24 for xx. Use ln⁑2β‰ˆ0.693\ln 2 \approx 0.693.

Example 36

hard
Find the equation of the tangent line to y=exy=e^x at x=1x=1. Use eβ‰ˆ2.718e \approx 2.718.

Example 37

hard
Solve ex=2eβˆ’xe^{x} = 2 e^{-x} for xx. Use ln⁑2β‰ˆ0.693\ln 2 \approx 0.693.

Example 38

hard
Compute lim⁑xβ†’0exβˆ’1x\lim_{x \to 0}\dfrac{e^x - 1}{x}.

Example 39

challenge
A population doubles every 5 years and grows continuously: P(t)=P0ertP(t)=P_0 e^{rt}. Find rr using ln⁑2β‰ˆ0.693\ln 2\approx 0.693.

Background Knowledge

These ideas may be useful before you work through the harder examples.

exponential function