Conditional Probability Math Example 1

Follow the full solution, then compare it with the other examples linked below.

Example 1

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In a class of 3030 students, 1818 play soccer, 1212 play basketball, and 66 play both. If a student plays soccer, what is the probability they also play basketball?

Solution

  1. 1
    We need P(BโˆฃS)=P(BโˆฉS)P(S)P(B \mid S) = \frac{P(B \cap S)}{P(S)}.
  2. 2
    P(BโˆฉS)=630=15P(B \cap S) = \frac{6}{30} = \frac{1}{5} and P(S)=1830=35P(S) = \frac{18}{30} = \frac{3}{5}.
  3. 3
    P(BโˆฃS)=1/53/5=13P(B \mid S) = \frac{1/5}{3/5} = \frac{1}{3}.

Answer

P(BโˆฃS)=13P(B \mid S) = \frac{1}{3}
Conditional probability restricts the sample space to only those outcomes where the given condition is true. Here we only consider the 1818 soccer players.

About Conditional Probability

The conditional probability P(AโˆฃB)P(A|B) is the probability of event AA occurring given that event BB has already occurred.

Learn more about Conditional Probability โ†’

More Conditional Probability Examples