Area Between Curves Math Example 4

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Example 4

medium
Find the area between y=x2y = x^2 and y=2xy = 2x.

Solution

  1. 1
    Intersections: x2=2xโ‡’x=0,2x^2=2x \Rightarrow x=0,2.
  2. 2
    On (0,2)(0,2): 2x>x22x > x^2 (test x=1x=1: 2>12>1).
  3. 3
    A=โˆซ02(2xโˆ’x2)โ€‰dx=[x2โˆ’x33]02=4โˆ’83=43A = \int_0^2(2x-x^2)\,dx = [x^2-\frac{x^3}{3}]_0^2 = 4-\frac{8}{3} = \frac{4}{3}.

Answer

43\frac{4}{3}
Find intersections, determine which curve is on top, integrate the difference.

About Area Between Curves

The area of the region enclosed between two functions f(x)f(x) and g(x)g(x) from x=ax = a to x=bx = b, computed as A=โˆซabโˆฃf(x)โˆ’g(x)โˆฃโ€‰dxA = \int_a^b |f(x) - g(x)|\,dx.

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