Example 2
hard Find the total area enclosed between y=x3โx and the x-axis. Solution
- 1
Zeros of x3โx=x(xโ1)(x+1): x=โ1,0,1. - 2
Sign check: on (โ1,0) the function is positive; on (0,1) it is negative. - 3
โซโ10โ(x3โx)dx=[4x4โโ2x2โ]โ10โ=0โ(41โโ21โ)=41โ. - 4
โซ01โ(x3โx)dx=41โโ21โ=โ41โ (negative; take absolute value). - 5
Total area =41โ+41โ=21โ.
When the curve crosses the axis, split at each zero and add absolute values of each piece to get the total geometric area.
About Area Between Curves
The area of the region enclosed between two functions f(x) and g(x) from x=a to x=b, computed as A=โซabโโฃf(x)โg(x)โฃdx.
Learn more about Area Between Curves โ