Area Between Curves Math Example 1

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Example 1

easy
Find the area between f(x)=x+2f(x) = x+2 and g(x)=x2g(x) = x^2 from x=โˆ’1x=-1 to x=2x=2.

Solution

  1. 1
    Intersections: x+2=x2โ‡’(xโˆ’2)(x+1)=0โ‡’x=โˆ’1,2x+2=x^2 \Rightarrow (x-2)(x+1)=0 \Rightarrow x=-1,2 (endpoints).
  2. 2
    At x=0x=0: f(0)=2>g(0)=0f(0)=2 > g(0)=0, so fโ‰ฅgf \geq g throughout.
  3. 3
    A=โˆซโˆ’12(x+2โˆ’x2)โ€‰dx=[x22+2xโˆ’x33]โˆ’12A = \int_{-1}^{2}(x+2-x^2)\,dx = \left[\frac{x^2}{2}+2x-\frac{x^3}{3}\right]_{-1}^{2}.
  4. 4
    F(2)=2+4โˆ’83=103F(2) = 2+4-\frac{8}{3} = \frac{10}{3}; F(โˆ’1)=12โˆ’2+13=โˆ’76F(-1)=\frac{1}{2}-2+\frac{1}{3}=-\frac{7}{6}.
  5. 5
    A=103+76=206+76=276=92A = \frac{10}{3}+\frac{7}{6} = \frac{20}{6}+\frac{7}{6} = \frac{27}{6} = \frac{9}{2}.

Answer

92\frac{9}{2}
Identify intersection points, confirm which function is on top, then integrate the difference over the interval.

About Area Between Curves

The area of the region enclosed between two functions f(x)f(x) and g(x)g(x) from x=ax = a to x=bx = b, computed as A=โˆซabโˆฃf(x)โˆ’g(x)โˆฃโ€‰dxA = \int_a^b |f(x) - g(x)|\,dx.

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