Adding and Subtracting Rational Expressions Math Example 4

Follow the full solution, then compare it with the other examples linked below.

Example 4

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Subtract 5xโˆ’3โˆ’2x+1\frac{5}{x-3} - \frac{2}{x+1}.

Solution

  1. 1
    LCD = (xโˆ’3)(x+1)(x-3)(x+1). 5(x+1)โˆ’2(xโˆ’3)(xโˆ’3)(x+1)=5x+5โˆ’2x+6(xโˆ’3)(x+1)\frac{5(x+1) - 2(x-3)}{(x-3)(x+1)} = \frac{5x+5-2x+6}{(x-3)(x+1)}.
  2. 2
    =3x+11(xโˆ’3)(x+1)= \frac{3x + 11}{(x-3)(x+1)}.

Answer

3x+11(xโˆ’3)(x+1)\frac{3x + 11}{(x-3)(x+1)}
When subtracting, distribute the negative to the entire second numerator: โˆ’2(xโˆ’3)=โˆ’2x+6-2(x-3) = -2x + 6. A common error is writing โˆ’2xโˆ’6-2x - 6 instead.

About Adding and Subtracting Rational Expressions

Adding or subtracting rational expressions by finding a least common denominator (LCD), rewriting each fraction with the LCD, then combining the numerators over the common denominator.

Learn more about Adding and Subtracting Rational Expressions โ†’

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