Adding and Subtracting Rational Expressions Math Example 2

Follow the full solution, then compare it with the other examples linked below.

Example 2

hard
Subtract xx+2โˆ’3x2+4x+4\frac{x}{x+2} - \frac{3}{x^2 + 4x + 4}.

Solution

  1. 1
    Step 1: Factor: x2+4x+4=(x+2)2x^2 + 4x + 4 = (x+2)^2. LCD = (x+2)2(x+2)^2.
  2. 2
    Step 2: x(x+2)(x+2)2โˆ’3(x+2)2\frac{x(x+2)}{(x+2)^2} - \frac{3}{(x+2)^2}.
  3. 3
    Step 3: Combine: x2+2xโˆ’3(x+2)2=(x+3)(xโˆ’1)(x+2)2\frac{x^2 + 2x - 3}{(x+2)^2} = \frac{(x+3)(x-1)}{(x+2)^2}.
  4. 4
    Check: At x=1x = 1: 13โˆ’39=13โˆ’13=0\frac{1}{3} - \frac{3}{9} = \frac{1}{3} - \frac{1}{3} = 0 and 4โ‹…09=0\frac{4 \cdot 0}{9} = 0 โœ“

Answer

(x+3)(xโˆ’1)(x+2)2\frac{(x+3)(x-1)}{(x+2)^2}
When one denominator is a factor of the other, the LCD is the higher-power denominator. After combining, try to factor the numerator for a fully simplified answer.

About Adding and Subtracting Rational Expressions

Adding or subtracting rational expressions by finding a least common denominator (LCD), rewriting each fraction with the LCD, then combining the numerators over the common denominator.

Learn more about Adding and Subtracting Rational Expressions โ†’

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