Stoichiometry Chemistry Example 4

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Example 4

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How many grams of NaCl\text{NaCl} form from 0.500.50 mol of Cl2\text{Cl}_2 reacting with excess sodium? (2Na+Cl2β†’2NaCl2\text{Na} + \text{Cl}_2 \rightarrow 2\text{NaCl}; molar mass of NaCl=58.44 g/mol\text{NaCl} = 58.44\,\text{g/mol})

Solution

  1. 1
    Use the mole ratio from the balanced equation: 11 mol Cl2\text{Cl}_2 produces 22 mol NaCl\text{NaCl}, so 0.500.50 mol Cl2\text{Cl}_2 produces 1.001.00 mol NaCl\text{NaCl}.
  2. 2
    Convert product moles to mass: 1.00Γ—58.44=58.4 g1.00 \times 58.44 = 58.4\,\text{g}.

Answer

58.4 gΒ ofΒ NaCl58.4\,\text{g of } \text{NaCl}
Stoichiometry uses the coefficients in a balanced equation as mole ratios. Once the product moles are known, convert to grams with the molar mass.

About Stoichiometry

The branch of chemistry that uses balanced chemical equations and mole ratios to calculate the precise quantities of reactants consumed and products formed in chemical.

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