Single Displacement Chemistry Example 4

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Example 4

hard
Zinc metal is placed in a copper(II) sulfate solution (CuSO4\text{CuSO}_4). The solution gradually loses its blue color and a reddish deposit forms. Write the balanced equation and explain what the color changes indicate.

Solution

  1. 1
    Balanced equation: Zn+CuSO4ZnSO4+Cu\text{Zn} + \text{CuSO}_4 \rightarrow \text{ZnSO}_4 + \text{Cu}.
  2. 2
    The blue color fading indicates Cu2+\text{Cu}^{2+} ions (which are blue) are being removed from solution as they gain electrons and become solid copper (the reddish deposit).
  3. 3
    Zinc is more reactive than copper (higher in the activity series), so it displaces copper from solution. Zinc dissolves as Zn2+\text{Zn}^{2+} ions, which are colorless.

Answer

Zn+CuSO4ZnSO4+Cu(single displacement)\text{Zn} + \text{CuSO}_4 \rightarrow \text{ZnSO}_4 + \text{Cu} \quad (\text{single displacement})
Observable changes (color loss, solid deposit) provide evidence that a chemical reaction has occurred. The activity series predicts which single displacement reactions will proceed.

About Single Displacement

A chemical reaction in which a free (uncombined) element that is more reactive displaces and replaces a less reactive element within a compound, producing a.

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