Neutralization Chemistry Example 2

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Example 2

medium
How many mL of 0.50 M NaOH0.50\,\text{M NaOH} are needed to neutralize 25 mL25\,\text{mL} of 0.30 M HCl0.30\,\text{M HCl}?

Solution

  1. 1
    Moles of HCl =0.025 L×0.30 M=0.0075 mol= 0.025\,\text{L} \times 0.30\,\text{M} = 0.0075\,\text{mol}.
  2. 2
    The reaction is 1:1, so moles of NaOH needed =0.0075 mol= 0.0075\,\text{mol}.
  3. 3
    Volume of NaOH =0.00750.50=0.015 L=15 mL= \frac{0.0075}{0.50} = 0.015\,\text{L} = 15\,\text{mL}.

Answer

15 mL of NaOH15\,\text{mL of NaOH}
Titration calculations use the relationship M1V1=M2V2M_1V_1 = M_2V_2 for 1:1 acid-base reactions. This allows us to determine unknown concentrations or volumes.

About Neutralization

A chemical reaction in which an acid and a base combine to produce water and an ionic compound called a salt, effectively canceling out the.

Learn more about Neutralization →

More Neutralization Examples

Example 1 easy

Write the balanced equation for the neutralization of hydrochloric acid with sodium hydroxide.

Example 3 easy

Write the neutralization reaction between sulfuric acid ([formula]) and potassium hydroxide ([formul

Example 4 medium

Hydrogen ions from an acid react with hydroxide ions from a base. What substance do those ions form

← All Neutralization Examples Neutralization Concept

Related Concepts

AcidBaseSaltTitration