Isotope Chemistry Example 3

Follow the full solution, then compare it with the other examples linked below.

Example 3

hard
Copper has two stable isotopes: 63Cu{}^{63}\text{Cu} and 65Cu{}^{65}\text{Cu}. The average atomic mass of copper is 63.5563.55 amu. Calculate the percent abundance of each isotope.

Solution

  1. 1
    Let xx = fraction of 63Cu{}^{63}\text{Cu}. Then 1โˆ’x1 - x = fraction of 65Cu{}^{65}\text{Cu}.
  2. 2
    Set up: 63x+65(1โˆ’x)=63.5563x + 65(1 - x) = 63.55. Simplify: 63x+65โˆ’65x=63.5563x + 65 - 65x = 63.55, so โˆ’2x=โˆ’1.45-2x = -1.45, x=0.725x = 0.725.
  3. 3
    63Cu{}^{63}\text{Cu}: 72.5%72.5\%, 65Cu{}^{65}\text{Cu}: 27.5%27.5\%.

Answer

63Cu:ย 72.5%,65Cu:ย 27.5%{}^{63}\text{Cu: } 72.5\%,\quad {}^{65}\text{Cu: } 27.5\%
When the average atomic mass is known, you can set up a linear equation to solve for the unknown abundances of two isotopes.

About Isotope

Atoms of the same element that have the same number of protons but different numbers of neutrons, giving them different mass numbers.

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