Dilution Chemistry Example 4

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Example 4

easy
How much 6.0 M6.0\,\text{M} hydrochloric acid is needed to prepare 250250 mL of 1.5 M1.5\,\text{M} HCl?

Solution

  1. 1
    Use the dilution equation M1V1=M2V2M_1V_1 = M_2V_2.
  2. 2
    V1=M2V2M1=1.5×2506.0=62.5 mLV_1 = \frac{M_2V_2}{M_1} = \frac{1.5 \times 250}{6.0} = 62.5\,\text{mL}.

Answer

62.5 mL62.5\,\text{mL}
Dilution changes concentration by adding solvent, not solute. The amount of solute stays constant, so M1V1=M2V2M_1V_1 = M_2V_2 balances the two solutions.

About Dilution

The process of decreasing the concentration of a solution by adding more solvent while keeping the total amount of solute constant.

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More Dilution Examples

Example 1 easy

How much water must be added to [formula] of [formula] to make a [formula] solution?

Example 2 medium

A stock solution of [formula] is [formula]. What volume is needed to prepare [formula] of [formula]

Example 3 easy

You dilute [formula] of [formula] to a final volume of [formula]. What is the new concentration?

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