Conservation of Mass Chemistry Example 2

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Example 2

medium
In a sealed container, 50.050.0 g of calcium carbonate decomposes: CaCO3→CaO+CO2\text{CaCO}_3 \rightarrow \text{CaO} + \text{CO}_2. If 28.028.0 g of CaO is produced, what mass of CO2\text{CO}_2 is released?

Solution

  1. 1
    Apply conservation of mass: mass of reactants == mass of products.
  2. 2
    50.0 g=28.0 g (CaO)+mCO250.0\,\text{g} = 28.0\,\text{g (CaO)} + m_{\text{CO}_2}.
  3. 3
    mCO2=50.0−28.0=22.0 gm_{\text{CO}_2} = 50.0 - 28.0 = 22.0\,\text{g}.

Answer

22.0 g of CO222.0\,\text{g of CO}_2
Conservation of mass allows us to calculate the mass of any one substance in a reaction if we know all the others. This principle holds whether the container is open or closed.

About Conservation of Mass

A fundamental law stating that in any chemical reaction, the total mass of all reactants exactly equals the total mass of all products, because atoms.

Learn more about Conservation of Mass →

More Conservation of Mass Examples

Example 1 easy

If [formula] g of hydrogen reacts with [formula] g of oxygen to form water, what is the total mass o

Example 3 easy

A student burns [formula] g of magnesium in air and obtains [formula] g of magnesium oxide. How much

Example 4 easy

If 12 g of magnesium reacts with oxygen to form 20 g of magnesium oxide in a closed container, how m

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